Rust JSON
How do I convert a JSON string to a struct in Rust?
Convert JSON to structs in Rust using serde_json crate. First, add serde = { version = "1.0", features = ["derive"] } and serde_json = "1.0" to Cargo.toml. Define your struct with derive macros: #[derive(Deserialize)] struct User { name: String, age: u32 }. Deserialize using: let user: User = serde_json::from_str(json_str)?. The ? operator handles errors elegantly. For complex JSON, match field names using #[serde(rename = "field_name")] attributes. Handle optional fields with Option<T>. Use serde_json::from_reader() for files or streams. For dynamic JSON structure unknown at compile time, use serde_json::Value instead of typed structs. Validate your JSON structure first with our JSON Editor at jsonconsole.com/json-editor to ensure it matches your struct definition. Serde provides excellent error messages when deserialization fails. Type safety ensures invalid JSON is caught at parse time rather than runtime. This is the idiomatic Rust approach to JSON handling.
Last updated: December 23, 2025
Previous
Is it worth migrating an existing .NET project to System.Text.Json?
Next
What is the difference between serde_json::Value and strongly typed structs?
Related Questions
What is the difference between serde_json::Value and strongly typed structs?
Understand the difference between serde_json::Value and strongly typed structs in Rust. Learn when to use each approach.
Do I always need to derive Serialize and Deserialize for Rust structs?
Learn when you need to derive Serialize and Deserialize in Rust. Understand serde requirements and custom implementations.
How do you handle missing or optional fields in serde_json?
Learn how to handle missing and optional fields in serde_json. Master Option types, default values, and nullable field handling in Rust.
Still have questions?
Can't find the answer you're looking for? Please reach out to our support team.